Solution to Problem 76



Congratulations to this week's winners

Shaun Lewis, Paul Leisher, Nathan Pauli, Ray Kremer

Solutions were submitted by Yan Fridman, Bill Webb, Emanuele Macri, Loranzo Pozzoli, Massimo Brigonone, Trevor Green.



It never happens!

Let's write  qh, qm, qs for the angles that the hour, minute and second hands make, measured in radians clockwise from 12:00.  In terms of t, the number of seconds since 12:00, these angles are given by

qh = ,  qm = ,  qs .

Let's assume that, as we look clockwise around the clock, we see first the hour hand, then the minute hand and the second hand.  For the angle between the hour hand and the minute hand to be 1200, we must have

 qh - qm = 2p/3 + 2pn,

for n a positive integer, 0 £ n £ 12.  Similarly, looking at the angle between the minute hand and the second hand, we must have

qm - qs = 2p/3 + 2pm,

for m a positive integer, 0 £ n £ 60.  Substituting the equations above, solving for t and equating the two gives

.
Solving for m in terms of n gives
m =,

an equation which does not yield an integer for 0 £ n £ 12.
 

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Page last updated 16 November 1999.