Solution to Problem 243


Correct solutions were submitted by Bill Webb, Ron Welch, Cee Ann Franklin, Nancy Schwarzkopf, Lou Cairoli, Farid Lian and Juan Carlos Marivela.

Let x be the length of the tether.
Let O be the center of the circle, P the point at which the tether attaches, and A and B the points on the circle that are x away from P.
The goat can reach the combination of two regions: the part of the circle centered at O with radius 10 that is outside chord AB and the part of the circle centered at P with radius x, again outside AB.

Consider a circle of radius r and a chord subtended by a central angle of 2 * c.
The area inside the circle and outside the chord is r2 * c - r2 * sin c * cos c.

Let t be the measure of angle POA and let g be the measure of angle APO.
By the law of cosines, x2 = 102 + 102 - 2 * 10 * 10 * cos t and 102 = 102 + x2 - 2 * 10 * x * cos g.

Combining all this information with the fact that the goat should be able to graze on half the field, we get a mildly messy equation in x.
We can't solve it exactly, but we can approximate the solution as closely as we like.
To two decimal places, the tether should be 11.59 feet long.

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